0=12x^2-6x-18

Solution for 0=12x^2-6x-18 equation:

0=12x^2-6x-18

We move all terms to the left:

0-(12x^2-6x-18)=0

We add all the numbers together, and all the variables

-(12x^2-6x-18)=0

We get rid of parentheses

-12x^2+6x+18=0

a = -12; b = 6; c = +18;
Δ = b2-4ac
Δ = 62-4·(-12)·18
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*-12}=\frac{-36}{-24}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*-12}=\frac{24}{-24}
=-1
$